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Title : Some Expected Questions Inwards Cgl Tier-2 2017 Which Y'all Must Solve
link : Some Expected Questions Inwards Cgl Tier-2 2017 Which Y'all Must Solve

Some Expected Questions Inwards Cgl Tier-2 2017 Which Y'all Must Solve

Q1. If a circle has a foursquare too a hexagon too the vertices of both deport on the circle’s circumference thus what is the ratio of the surface area of the two?

Solution: Ratio of Square too Hexagon = b²/6 × √3/4 a²

= (4/6√3)b²/a²

= 4/6√3 (√2r/r²)²

= four × 2 × r²/6 × √3× r²

= 4/3√3

= 4: 3√3

Q2. Area of which of the next is maximum when perimeter is equal?

circle, square, triangle

Solution: Circle’s surface area is maximum for a given fixed value of perimeter.

Q3. Sum of the squares of 3 numbers is 323. If the heart too somebody of squares of 2 numbers is twice of the tertiary number, detect the production of 3 numbers.

Sol: Let the numbers endure x, y too z

Given,

x² + y² + z² = 323       — (1)

x² + y² = 2z                 — (2)

Put 2 into ane too solve it.

Q4. Find Compound Interest on 4000 rupees for four yr at 10%rate of interest, compounded annually.

Solution: CI = P(1 + r/100)ⁿ – P, where P is main amount; r is the charge per unit of measurement of interest; too n is divulge of years.

Put the values too solve.

Q5. Find the value of (1+sec20° +cot70°)(1-cosec20° + tan70°)

Solution: (1 + 1/cos20° + cos70°/sin70°)(1 – 1/sin20° + sin70°/cos70°)

We know that sin(90 – θ) = cosθ

Hence, the aspect volition become:

(1 + 1/cos20° + sin20°/cos20°)(1 – 1/sin20° + cos20°/sin20°)

(cos20° + ane + sin20°)(sin20° – ane + cos20°)/sin20°cos20°

= [sin220 + cos220 + 2sin20.cos20 – 1]/sin20°cos20°

We know that, sin2θ + cos2θ = 1

⇒ [1 + 2sin20.cos20 – 1]/sin20°cos20°

⇒ 2sin20.cos20/sin20°cos20°

= 2

Q6. Difference inwards chemical compound involvement is INR 723 at 20% for a yearly or one-half yearly basis. Find the Sum.

Sol: Since, the yearly involvement charge per unit of measurement is 20%, the one-half yearly involvement charge per unit of measurement volition endure 10%

Given,

P[1 + 10/100]² – P[1 + 20/100]¹ = 723

Solve it too larn the value of P.

Thus the article Some Expected Questions Inwards Cgl Tier-2 2017 Which Y'all Must Solve

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