Ssc Cgl 2018 | Advanced Maths Questions Amongst Answers & Explanations Inwards Hindi

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Title : Ssc Cgl 2018 | Advanced Maths Questions Amongst Answers & Explanations Inwards Hindi
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Ssc Cgl 2018 | Advanced Maths Questions Amongst Answers & Explanations Inwards Hindi

Advanced Maths Questions inwards Hindi
SSC CGL Q1: यदि x3 + 2x2 – 5x + k  (x+1) से विभाजित है, तो k का मान क्या है?
(1)– 6
(2)– 1
(3)0
(4)6
SSC CGL Q2: यदि 3x + [1/(5x)] = 7, तो 5x/(15x2 + 15x + 1) का मान क्या है?
(1)1/5
(2)1/10
(3)2/5
(4)10

SSC CGL Q3: यदि x + [1/(4x)] = 5/2, तो (64x6 + 1)/8x3 का मान क्या है?
(1)110
(2)115
(3)125
(4)140

SSC CGL Q4: यदि x2 + x = 19, तो (x + 5)2 + [1/(x + 5)2] का मान क्या है?
(1)77
(2)79
(3)81
(4)83

Answer & Solution:

SSC CGL Solution 1:
यदि x3 + 2x2 – 5x + k  (x+1) से विभाजित है, इसका मतलब है कि जब हम x = -1 रखते हैं, बहुपद का मान शून्य होगा।  
(-1)3 + 2(-1)2 – 5* -1 + k = 0 या, -1 +2*1 +5 + k = 0
या, -1 +2 + five + k = 0 या, k = -6
उत्तर विकल्प(1) है।

SSC CGL Solution 2:
व्यंजक को 5x से भाग करने पर,   1/ (3x + iii + 1/5x) या, 1/ (7 + 3) = 1/10
उत्तर विकल्प(2) है।

SSC CGL Solution 3:
(64x6 + 1)/8x3 = 8x3 + [1/8x3] और, x + [1/(4x)] = 5/2
या, 2x + [1/2x] = 5
[2x + {1/2x}]3 = 8x3 + {1/8x3} + 3*2x*1/2x*[2x + {1/2x}] या, [5]3 = 8x3 + {1/8x3} + 3*1*5
या, 8x3 + {1/8x3} = 125 - fifteen = 110
उत्तर विकल्प(1) है।

SSC CGL Solution 4:
माना कि (x+5) = a या, x = a - five अब, x2 + x = 19
या, (a-5)2 + (a-5) = 19
या, a2 -10a + 25 + a - five = nineteen या, a2 -9a + i = 0
या, a2 + i = 9a या, a + 1/a = nine
दोनों तरफ वर्ग करने पर,
(a + 1/a)2 = 81
a2 + 1/a2 + ii = 81
a2 + 1/a2 = 81 - ii = 79
इसलिए,, (x + 5)2 + [1/(x + 5)2] = 79
उत्तर विकल्प(2) है।


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